x^2-4x+8=2x-2

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Solution for x^2-4x+8=2x-2 equation: 



x^2-4x+8=2x-2

We move all terms to the left:

x^2-4x+8-(2x-2)=0

We get rid of parentheses

x^2-4x-2x+2+8=0

We add all the numbers together, and all the variables

x^2-6x+10=0

a = 1; b = -6; c = +10;
Δ = b2-4ac
Δ = -62-4·1·10
Δ = -4
Delta is less than zero, so there is no solution for the equation

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